4x^2-100x+525=0

Solution for 4x^2-100x+525=0 equation:

4x^2-100x+525=0

a = 4; b = -100; c = +525;
Δ = b2-4ac
Δ = -1002-4·4·525
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-40}{2*4}=\frac{60}{8}
=7+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+40}{2*4}=\frac{140}{8}
=17+1/2
$